General Aptitude Study Materials for Competitive Exams

General Aptitude

Arithmetic Aptitude Data Interpretation

Q. What is the area of a square with a side length of 4 m?

A. 8 m²
B. 12 m²
C. 16 m²
D. 20 m²

Solution

Area = side × side = 4 m × 4 m = 16 m².

Correct Answer: C — 16 m²

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Q. What is the area of a trapezoid with bases of 10 m and 6 m, and a height of 4 m?

A. 40 m²
B. 32 m²
C. 24 m²
D. 36 m²

Solution

Area = 1/2 × (base1 + base2) × height = 1/2 × (10 m + 6 m) × 4 m = 32 m².

Correct Answer: B — 32 m²

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Q. What is the area of a trapezoid with bases of 10 meters and 6 meters, and a height of 4 meters?

A. 40
B. 32
C. 36
D. 28

Solution

Area = (1/2) × (base1 + base2) × height = (1/2) × (10 + 6) × 4 = 32 square meters.

Correct Answer: B — 32

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Q. What is the average of the first five decimal fractions?

A. 0.1
B. 0.2
C. 0.3
D. 0.4

Solution

The first five decimal fractions are 0.1, 0.2, 0.3, 0.4, 0.5. Average = (0.1 + 0.2 + 0.3 + 0.4 + 0.5) / 5 = 0.3.

Correct Answer: B — 0.2

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Q. What is the average of the first five prime numbers?

A. 5
B. 6
C. 7
D. 8

Solution

The first five prime numbers are 2, 3, 5, 7, 11. Average = (2 + 3 + 5 + 7 + 11) / 5 = 28 / 5 = 5.6.

Correct Answer: C — 7

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Q. What is the average of the following numbers: 0.5, 0.75, 1.25?

A. 0.75
B. 0.85
C. 0.95
D. 1.05

Solution

Average = (0.5 + 0.75 + 1.25) / 3 = 2.5 / 3 = 0.8333, which rounds to 0.75

Correct Answer: A — 0.75

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Q. What is the average of the numbers 0.5, 0.75, and 1.25?

A. 0.75
B. 0.85
C. 0.65
D. 0.95

Solution

Average = (0.5 + 0.75 + 1.25) / 3 = 2.5 / 3 = 0.75

Correct Answer: A — 0.75

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Q. What is the average of the numbers 10, 20, 30, 40, and 50?

A. 30
B. 25
C. 35
D. 40

Solution

Average = (10 + 20 + 30 + 40 + 50) / 5 = 150 / 5 = 30.

Correct Answer: A — 30

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Q. What is the average of the numbers 10, 20, 30, and 40?

A. 25
B. 30
C. 35
D. 40

Solution

Average = (10 + 20 + 30 + 40) / 4 = 100 / 4 = 25.

Correct Answer: B — 30

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Q. What is the average of the numbers 10, 20, and 30?

A. 15
B. 20
C. 25
D. 30

Solution

The average is (10 + 20 + 30) / 3 = 60 / 3 = 20.

Correct Answer: B — 20

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Q. What is the average sales of Product A over the four quarters?

A. 600
B. 700
C. 800
D. 900

Solution

Total sales for Product A over four quarters is 3200. Average = 3200 / 4 = 800.

Correct Answer: C — 800

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Q. What is the average sales per product in Q3?

A. $2000
B. $2500
C. $3000
D. $3500

Solution

Total sales in Q3 were $10000 across 4 products, so the average is $2500.

Correct Answer: B — $2500

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Q. What is the average sales per quarter for Product C?

A. $2000
B. $2500
C. $3000
D. $3500

Solution

Product C's total sales of $12000 divided by 4 quarters equals $3000.

Correct Answer: C — $3000

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Q. What is the Banker's Discount on a bill of $2500 due in 9 months at a rate of 8%?

A. $150
B. $120
C. $100
D. $180

Solution

Banker's Discount = (2500 x 8 x 9/12) / 100 = $150

Correct Answer: A — $150

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Q. What is the Banker's Discount on a bill of $500 due in 3 months at a rate of 6% per annum?

A. $7.50
B. $8.00
C. $9.00
D. $10.00

Solution

Banker's Discount = (Principal x Rate x Time) / 100 = (500 x 6 x 3/12) / 100 = $7.50

Correct Answer: A — $7.50

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Q. What is the Banker's Discount on a bill of Rs. 2000 due in 4 months at 15% per annum?

A. Rs. 100
B. Rs. 80
C. Rs. 60
D. Rs. 120

Solution

Banker's Discount = (2000 * 15 * 4/12) / 100 = Rs. 100.

Correct Answer: B — Rs. 80

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Q. What is the Banker's Discount on a loan of $10000 for 2 years at 5% per annum?

A. $1000
B. $500
C. $2000
D. $300

Solution

Banker's Discount = 10000 × 5/100 × 2 = $1000.

Correct Answer: A — $1000

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Q. What is the Banker's Discount on a loan of $10000 for 2 years at 6%?

A. $1200
B. $600
C. $800
D. $1000

Solution

Banker's Discount = 10000 × 6/100 × 2 = $1200.

Correct Answer: A — $1200

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Q. What is the Banker's Discount on a loan of $1500 for 2 years at 6% per annum?

A. $180
B. $120
C. $90
D. $60

Solution

Banker's Discount = 1500 × 6/100 × 2 = $180.

Correct Answer: A — $180

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Q. What is the Banker's Discount on a loan of $2500 for 2 years at 6%?

A. $300
B. $200
C. $150
D. $100

Solution

Banker's Discount = 2500 x 6/100 x 2 = $300.

Correct Answer: A — $300

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Q. What is the Banker's Discount on a loan of $6000 for 2 years at 9% per annum?

A. $1080
B. $720
C. $540
D. $900

Solution

Banker's Discount = 6000 × 9/100 × 2 = $1080.

Correct Answer: A — $1080

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Q. What is the Banker's Discount on a sum of $1500 for 2 years at 15% per annum?

A. $450
B. $300
C. $225
D. $150

Solution

Banker's Discount = 1500 × 15/100 × 2 = $450.

Correct Answer: A — $450

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Q. What is the Banker's Discount on a sum of $2500 for 2 years at 12% per annum?

A. $600
B. $500
C. $300
D. $400

Solution

Banker's Discount = 2500 × 12/100 × 2 = $600.

Correct Answer: A — $600

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Q. What is the banker's discount on a sum of $5000 due in 5 years at 8% per annum?

A. $2000
B. $1500
C. $1000
D. $800

Solution

Banker's Discount = P × R × T / 100 = 5000 × 8 × 5 / 100 = $2000.

Correct Answer: C — $1000

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Q. What is the bankers discount on a sum of $10000 due in 4 years at 5%?

A. $2000
B. $1000
C. $500
D. $400

Solution

Bankers Discount = (10000 × 5 × 4) / 100 = $2000.

Correct Answer: B — $1000

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Q. What is the compound interest on $1000 for 2 years at a rate of 6% per annum?

A. $126.00
B. $120.00
C. $136.00
D. $140.00

Solution

Compound Interest = 1000(1 + 0.06)^2 - 1000 = 1000(1.1236) - 1000 = 1123.60 - 1000 = 126.00

Correct Answer: A — $126.00

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Q. What is the compound interest on $1200 at a rate of 10% per annum for 1 year?

A. $120.00
B. $100.00
C. $110.00
D. $130.00

Solution

Compound Interest = P(1 + r/n)^(nt) - P = 1200(1 + 0.10/1)^(1*1) - 1200 = 1200(1.10) - 1200 = 120.00

Correct Answer: A — $120.00

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Q. What is the compound interest on $1200 at a rate of 7% per annum for 5 years?

A. $420.00
B. $450.00
C. $430.00
D. $440.00

Solution

Compound Interest = P(1 + r/n)^(nt) - P = 1200(1 + 0.07/1)^(1*5) - 1200 = 1200(1.402552) - 1200 = 420.00

Correct Answer: A — $420.00

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Q. What is the compound interest on $1200 for 3 years at a rate of 9% per annum?

A. $350.00
B. $400.00
C. $450.00
D. $500.00

Solution

CI = A - P; A = P(1 + r)^n = 1200(1 + 0.09)^3 = 1200(1.295029) = $1554.03, CI = 1554.03 - 1200 = $354.03.

Correct Answer: B — $400.00

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Q. What is the compound interest on $2000 at a rate of 10% per annum for 2 years?

A. $400
B. $220
C. $242
D. $200

Solution

Compound Interest = P(1 + r/n)^(nt) - P = 2000(1 + 0.1)^2 - 2000 = 2000(1.21) - 2000 = $242.

Correct Answer: C — $242

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General Aptitude

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