Total balls = 3 + 5 = 8. Probability of red ball = 3/8.

Work done in 5 days = 5/15 = 1/3 of the task.

Apples left = Initial apples - Apples given away = 3 - 1 = 2.

Total balls = 3 + 2 + 5 = 10. Fraction of red balls = 3/10.

Total parts = 2 + 3 + 5 = 10; B's share = (3/10) × 200 = $60.

Total parts = 2 + 3 + 5 = 10. B's share = (3/10) × 200 = 60.

The HCF of 60, 72, and 90 is 18, as it is the largest number that divides all three.

The LCM of 6 and 14 is 42, as it is the smallest number that is a multiple of both.

The LCM of 8 and 12 is 24, as it is the smallest number that is a multiple of both 8 and 12.

Work done = Workers × Days; Total work = 12 × 15 = 180 worker-days; 6 workers will take 180/6 = 30 days.

Work done = Workers × Days. 12 workers × 10 days = 120 worker-days. 6 workers will take 120 / 6 = 20 days.

Work done = Workers × Days. Total work = 12 × 15 = 180. For 6 workers, Days = 180 / 6 = 30 days.

3a + 4 = 19 => 3a = 15 => a = 5.

Cost of 1 apple = $10 / 5 = $2. Cost of 12 apples = 12 × $2 = $24.

The LCM can be found using the formula: LCM = (Product of the numbers) / HCF. Thus, LCM = 450 / 15 = 30.

The product of the two numbers can be found using the formula: Product = LCM * HCF. Thus, Product = 72 * 8 = 576.

The product of the two numbers can be found using the formula: Product = LCM * HCF. Thus, Product = 84 * 12 = 1008.

New price after increase = 40 + 25% of 40 = 50; New price after decrease = 50 - 20% of 50 = 40.

The HCF of 48 and 180 is 12, as it is the largest number that divides both.

Let the numbers be 2x and 7x. Then, HCF(2x, 7x) = x = 12, so x = 12. The numbers are 24 and 84. Their sum is 108.

The HCF of 45, 75, and 105 is 15, as it is the largest number that divides all three.

The LCM of 14 and 35 is 70, as it is the smallest number that is a multiple of both.

The LCM of 9, 12, and 15 is 180, as it is the smallest number that is a multiple of all three.