Q. How many lone pairs are present in the Lewis structure of water (H2O)?
Solution
In the Lewis structure of water, there are 2 lone pairs on the oxygen atom.
Correct Answer:
B
— 1
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Q. What is the bond angle in a tetrahedral molecule?
-
A.
90 degrees
-
B.
120 degrees
-
C.
109.5 degrees
-
D.
180 degrees
Solution
In a tetrahedral molecule, the bond angle is approximately 109.5 degrees.
Correct Answer:
C
— 109.5 degrees
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Q. What is the bond order of O2?
Solution
The bond order of O2 is 2, indicating a double bond between the two oxygen atoms.
Correct Answer:
B
— 2
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Q. What is the hybridization of the central atom in SF6?
-
A.
sp
-
B.
sp2
-
C.
sp3
-
D.
sp3d2
Solution
The central atom sulfur in SF6 has sp3d2 hybridization.
Correct Answer:
D
— sp3d2
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Q. What is the molecular geometry of ammonia (NH3)?
-
A.
Linear
-
B.
Trigonal planar
-
C.
Tetrahedral
-
D.
Trigonal pyramidal
Solution
Ammonia (NH3) has a trigonal pyramidal molecular geometry due to one lone pair on nitrogen.
Correct Answer:
D
— Trigonal pyramidal
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Q. What type of hybridization occurs in a molecule with a trigonal planar geometry?
-
A.
sp
-
B.
sp2
-
C.
sp3
-
D.
dsp3
Solution
Trigonal planar geometry corresponds to sp2 hybridization.
Correct Answer:
B
— sp2
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Q. Which of the following has the highest electronegativity?
-
A.
Fluorine
-
B.
Oxygen
-
C.
Nitrogen
-
D.
Chlorine
Solution
Fluorine has the highest electronegativity of all elements.
Correct Answer:
A
— Fluorine
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Q. Which of the following molecules has a linear shape?
-
A.
CH4
-
B.
CO2
-
C.
NH3
-
D.
H2O
Solution
CO2 has a linear shape due to its double bonds and no lone pairs on the central atom.
Correct Answer:
B
— CO2
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Q. Which of the following molecules is polar?
-
A.
CCl4
-
B.
CO2
-
C.
HCl
-
D.
CH4
Solution
HCl is a polar molecule due to the difference in electronegativity between hydrogen and chlorine.
Correct Answer:
C
— HCl
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Q. Which type of bond is formed between sodium and chlorine in NaCl?
-
A.
Covalent
-
B.
Ionic
-
C.
Metallic
-
D.
Hydrogen
Solution
An ionic bond is formed between sodium and chlorine in NaCl.
Correct Answer:
B
— Ionic
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